"AST1CAL3 EQUATION VARIABLE","08-31-1993","18:35:44"
"Rม=(COSD(้[I])-((N[T]/N[I])^2-SIND(้[I])^2)^0.5)/(COSD(้[I])+((N[T]/N[I])^2-SIND(้[I])^2)^0.5) Rบ=((N[T]/N[I])^2*COSD(้[I])-((N[T]/N[I])^2-SIND(้[I])^2)^0.5)/((N[T]/N[I])^2*COSD(้[I])+((N[T]/N[I])^2-SIND(้[I])^2)^0.5) R[N]=RND(100*0.5*(Rม^2+Rบ^2))"
"OPTICS: REFLECTANCE OF NATURAL LIGHT AT AN INTERFACE.                                     incident      reflected                                                              \/        /\                                                                      \     /  air   n[i]                                                    angle ้[i] \ /                                                               ษออออออออออออออออออออออออออออออออป                                              ฬ     glass interface      n[t]  ถ                                              ศออออออออออออออออออออออออออออออออผ                        R[N] is % reflectance of natural light which is the average of the magnitudes   of its perpendiclar Rม and parallel Rบ components.  ้[I] is the angle of        incidence of the beam in degrees.  N[I] is the index of refraction of air (=1.0)and N[T] is the index of refraction of the glass substrate.                     *** Answer to Problems ***                                (c) PCSCC, Inc., 1993 Set N[I]=1, N[T]=1.61 and ้[I]=75.  The reflectance is 27.1%.                                         Type any key to exit.                                                                                                                                    || (a) What percentage of incoming unpolarized light is reflectedat an air-glass interface (N[glass]=1.61) for a beam of natural light incident  at 75๘?  Type comma key to see answers. Type (F2) to return to application file."
6
-.6653652040734061,0,""
-.3150533609387719,0,""
27.1,0,""
75,0,""
1.61,0,""
1,0,""
1
0
0