"AST3CAL3 EQUATION VARIABLE","12-31-1993","10:27:20" "T_?=T_LOW+(V_?-V_LOW)/(V_HIGH-V_LOW)*(T_HIGH-T_LOW) WARNING=888888*SIGN(ABS(USF(T_HIGH-T_?)-USF(T_?-T_LOW))+ABS(USF(V_HIGH-V_?)-USF(V_?-V_LOW)))" "INTERPOLATION, LINEAR. Interpolate thermocouple voltage V_? to temperature T_?. Enter T_high, T_low, V_high and V_low and then V_?. WARNING=888888 means that either T_? or V_? falls outside of the ranges T_High to T_low and V_high to V_low, respectively. T_high 컴컴 <-------- 컴컴 V_high V_high maps into T_high V_low maps into T_low. T_? 컴컴 <-------- 컴컴 V_? V_? maps into T_? T_low 컴컴 <-------- 컴컴 V_low Assume linear mapping. *** Answers to problems *** (a) 138.1 mV is between 136.6 and 140.4 so use this data for interpolation. Set T_HIGH to 105, T_LOW to 95, V_HIGH to 140.4 and V_LOW to 136.6. Set V_? to 138.1. Result is T_?=98.95. (b) Move cursor to V_?. Type S. For variable name, use T_?. Type (enter). For value, type (end esc) 104 (enter). For search range, use default, type (enter). Result is V_? = 140.02. ||A thermocouple has temperature vs. voltage calibration data of (85 �C, 132.7 mV), (95, 136.6) and (105, 140.4). (a) What is the temperature when the voltage reads 138.1 mv? and (b) what is the voltage when the temperature is at 104 �C? Type comma key to see answers. Type (F2) to return to application file." 7 103.9999999999999,0,"" 0,0,"" 140.02,0,"" 136.6,0,"" 140.4,0,"" 105,0,"" 95,0,"" 1 0 0