"AST1CAL3 EQUATION VARIABLE","11-16-1993","19:12:39" "TRANSVERSE_MAGNIFICATION=M[T]+(1-SIGN(ABS(M[T])))*-S[I]/NZE(S[O]) IMAGE_DISTANCE=S[I]+(1-SIGN(ABS(S[I])))*-S[O]*M[T] OBJECT_DISTANCE=S[O]+(1-SIGN(ABS(S[O])))*-S[I]/NZE(M[T]) FOCAL_LENGTH=1/NZE(1/NZE(OBJECT_DISTANCE)+1/NZE(IMAGE_DISTANCE))" "THIN LENS IMAGERY, CHARACTERISTICS for REAL OBJECTS, GAUSSIAN. A summary of object/image properties for concave and convex lenses follows. (enter 2 of 3 values and leave unknown as 0, program will calculate.) Lens OBJECT <-------------------- IMAGE -------------------> Location Type Location Orient. rel. size CNCV anywhere virtual |S[I]<|F| erect minfied CNVX ìS[I]>2*f invert. magnified CNVX S[O]=F ñì CNVX S[O]S[O] erect magnified F = focal length Transverse magnification: M[T] < 0 inverted |M[T]| < 1 minified *** Answer(s) to problem *** (c) PCSCC, Inc., 1993 This problem is solved by approximation. Image height is not required. Set M[T]=0, S[I]=0 and S[O]=100. Move cursor to S[I], type S and type (end esc) FOCAL_LENGTH (enter). For value type (end esc) 30 (enter). Use default for range, type (enter). Trans_mag=-.43, image at 43.9. Curly is inverted and minified. ||A 10 cm tall statue of Curly Howard is sitting 100 cm from a positive (converging) lens of 30 cm focal length. (a) Describe Curly's image. Type comma key to see answer. Type (F2) to return to application file." 7 -.4285714285714285,0,"" 42.85714285714285,0,"" 100,0,"" 30,0,"" 0,0,"" 100,0,"" 42.85714285714285,0,"" 1 0 0