"AST1CAL3 EQUATION VARIABLE","11-07-1993","12:13:14"
"RANGE=V0^2/G*SIND(2*THETA) TOF=2*V0/G*SIND(THETA) HEIGHT=V0*SIND(THETA)*TIME-0.5*G*TIME^2"
"MOTION of PROJECTILES in UNIFORM GRAVITY.                      Without air resistance, a projectiles shot off at an angle THETA with respect   to a flat surface has a range RANGE and time of filght TOF that depends on its  initial velocity, V0, gravity G and the angle of elevation THETA.                                     *  *  *                                                   shot at           *             *                                               VELINIT  /     *                   *                                                   /    *                         *                                              /   *___<THETA______________________*_hits surface at time TOF                                                                                             G=gravity: 32 ft/s^2 or 9.8 m/s^2, V0=initial velocity, THETA is the angle of   elevation in degrees.                                                                                                          (c) Copyright PCSCC, Inc., 1993  *** Answer to problem ***                                                       Type ?  then (esc) 0 (enter) to set all variables to zero. Set GRAVITY=32       ft/s^2, THETA=40 degrees, set V0=70 ft/s.  The RANGE=150.8 ft and TOF=2.82 s.   Note only equation TIME is active (followed by equal sign) and TIME is the plot coordinate (followed by colon). Type P, then (esc) 0 to TOF (enter).  Type E to exit plot screen.  Notice, maximum height = 31.6 ft occurs at about 1.45 s.                    ||A football is thrown with a perfect spiral at an initial       velocity of 70 ft/s an at an angle of 40 degrees with respect to the horizontal.(a) Plot the football's height vs. time.                                                Type comma key to see answers.  Type (F2) to return to helpfile."
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