"AST1CAL3 EQUATION VARIABLE","10-21-1993","21:38:47" "OBJECT_DISTANCE=S[O]+(1-SIGN(ABS(S[O])))*S[I]*-.5*R/(S[I]+R/2) IMAGE_DISTANCE=S[I]+(1-SIGN(ABS(S[I])))*S[O]*-.5*R/(S[O]+R/2) RADIUS=R+(1-SIGN(ABS(R)))*-2*S[O]*S[I]/(S[I]+S[O]+1E-30) FOCUS=-RADIUS/2 MAGNIFICATION=-IMAGE_DISTANCE/(OBJECT_DISTANCE+1E-30)" "SPHERICAL REFRACTING MIRRORS, IMAGE vs MAGNIFICATION. A diagram of the Problem is shown below. Mirror is represented by 's'. s ú oú S = source object ú ø s ø V = vertex of sphere ú ø s ø P C P = image (between F and C) S úøú ú ú ú ú ú ú ú úoú ú úøo ú ú o R = 2 * F | V|s | úø | | s ú|ø R S[O] = distance S to vertex | | sø | S[I] = distance vertex to image |-------S[O]---------|-S[I]-| C = center of sphere R = radius curvat. (c) Copyright PCSCC, Inc., 1993 Sign Convention: S[O] + means its left of vertex V focus + means concave S[I] + means its left of vertex V focus - means convex R + means center C is right of V *** Answer(s) to problem *** Solve for FOCUS (focal length) by approximation. Set R=10 (a guess). Set S[I]=0 and S[O]=150. Move cursor to R. Type S. For variable, type (end esc) FOCUS (enter). For value, type 400 (enter) and for range, use default, type (enter). R=-800 ( C is left of V, concave) and S[I]=-240 to right of V, virtual, erect and magnified. ||An eraser 5 cm tall sits 150 cm in front of a concave mirror offocal length 400 cm. (a) Describe the image. Type comma key to see answer. Type (F2) to return to application file." 8 150,0,"" -4.838709677419355,0,"" 10,0,"" -5,0,"" 3.225806451612903D-02,0,"" 150,0,"" 10,0,"" 0,0,"" 1 0 0